A train travelling at a uniform speed for 360km would have taken 48 minutes less to travel the same distance if its speed were 5km/hr more.Find the orginal speed of train.
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let the usual speed be x km/hr
let the time taken be y hrs
xy=360km →y=360/x
(x+5)(y-48/60)=360
(x+5)(360/x-48/60)=360 after this
x=50 km/hr
let the time taken be y hrs
xy=360km →y=360/x
(x+5)(y-48/60)=360
(x+5)(360/x-48/60)=360 after this
x=50 km/hr
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