a train travelling at a uniform speed passes by a platform 220 M long in 30 seconds and another platform 325 M long in 39 seconds find the length of the train and the speed of the train
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Answered by
85
Given s = t + 220/30 ------ (1)
and s = t + 325/39 ------ (2)
on solving (1) and (2), we get
39(t + 220) = 30(t + 325)
39t + 8580 = 30t + 9750
9t = 1170
t = 130 metres
Substitute in (1), we get
Speed = 130 + 220/30
= 350/30
= 11.66 m/sec
On converting it to km/hr, we get
S = 3600 * 11.66/1000
= 41.9
= ~42
and s = t + 325/39 ------ (2)
on solving (1) and (2), we get
39(t + 220) = 30(t + 325)
39t + 8580 = 30t + 9750
9t = 1170
t = 130 metres
Substitute in (1), we get
Speed = 130 + 220/30
= 350/30
= 11.66 m/sec
On converting it to km/hr, we get
S = 3600 * 11.66/1000
= 41.9
= ~42
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Answered by
41
L of platform =220m
30sec=220m
39sec=325m
Subtract 325and220=105
S=10/9=35/3
35/3*18/5=42km/hr
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