a train travelling at the rate 66.6 km/h passes a hole in 9 seconds and a platform in 29 seconds what is the length of the platform
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Answered by
3
Answer:
370 m
Step-by-step explanation:
Find the distance traveled in 1 second:
Given speed = 66.6 km/h
1 hour = 66.6 km = 66600 m
1 min = 66600 ÷ 60 = 1110 m
1 sec = 1110 ÷ 60 = 18.5 m
Find the length of the train:
1 second = 18.5 m
9 seconds = 18.5 x 9 = 166.5 m
Find the distance traveled in 29 seconds
1 second = 18.5 m
29 seconds = 18.5 x 29 = 536.5 m
Find the length of the platform:
Length of the platform = 536.5 - 166.5 = 370 m
Answer: The length of the platform is 370 m
Answered by
1
speed of train = 66.6 km/h
it means, train moves 66.6 km in 1 hour
or, train moves 66600 m in 3600 seconds
or, train moves 66600/3600 m in 1 seconds
or, train moves 111/6 m in 1 seconds
or, train moves 111/6 × 9 = 333/2 = 166.5 m in 9 seconds
so, length of train = distance travelled by train in 9 seconds = 166.5 m
let length of platform is L
then, length of platform + length of train = speed of train × time taken to cross platform
= 66.6 × 5/18 × 29
= 536.5 m
so, length of platform + 166.5 m = 536.5 m
length of platform = 536.5 - 166.5 = 370m
it means, train moves 66.6 km in 1 hour
or, train moves 66600 m in 3600 seconds
or, train moves 66600/3600 m in 1 seconds
or, train moves 111/6 m in 1 seconds
or, train moves 111/6 × 9 = 333/2 = 166.5 m in 9 seconds
so, length of train = distance travelled by train in 9 seconds = 166.5 m
let length of platform is L
then, length of platform + length of train = speed of train × time taken to cross platform
= 66.6 × 5/18 × 29
= 536.5 m
so, length of platform + 166.5 m = 536.5 m
length of platform = 536.5 - 166.5 = 370m
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