Question

A train travelling from stationary position and moving with a uniform acceleration attains a speed of 36 km/hr in 10 minutes. Find acceleration

Answer 1

Answer:

1/60 m/s

Explanation:

v=u+at

therefore, v=36km/h=10m/s

u=0

t=10min=600sec

therefore 10=0+600a

a=10÷600=(1/60)m/s

Answer 2

Explanation:

u=0

v=36km/h =36*5/18 =10m/s

t=10 min =10*60sec =600sec

a=?

a= v-u/t

a=10-0/600

a=1/60m/s²

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