Question

A train travels 180 kilometre at a uniform speed if the speed had been 6 km per hour more it would have taken 1 hour less for the same journey find the speed of the train​

Answer 1

Answer:

Step-by-step explanation:

Let the original speed=x

distance=180km

Time,t=180/x

if the speed had been 6km/h more

t-1=180/x+6

180/x-1=180/x+6

180/x-180/x+6=1

180(x+6)-180x/x(x+6)=1

180x+1080-180x/x^{2} +6x=1

1080=X2+6x

x2+6x-1080=0

x2+36x-30x-1080=0

x(x+36)-30(x+36)=0

(x+36)(x+30)=0

x=-36 or x=30

since speed cannot be negative

Therefore speed original speed =30km/h