Question

A Train travels 360 km at a Uniform
speed. If speed had been 5 km/ hr more
it would have taken 1 hour less for the
same journey find the speed of the train ? For SSLC
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Answer 1

Question:-

A Train travels 360 km at a Uniform  speed. If speed had been 5 km/ hr more  it would have taken 1 hour less for the  same journey find the speed of the train?  

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Solution:-

Let the original speed of the train be x km/h.

Time taken to cover a distance of 360 km =  360/x hours.

New speed of the train = (x+5) km/h.

Time taken to cover a distance of 360 km at new speed = 360/x+5 hours.

Since, the train takes 1 hour less time,

∴ 360/x - 360/ x+5 = 1

⇒360 (x+5-x)/x(x+5) = 1

⇒360 (5) = x² + 5x

⇒1800 = x² + 5x

⇒x² + 5x - 1800 = 0

⇒x² + 45x - 40x - 1800 = 0

⇒x (x+45) - 40( x +45) = 0

⇒(x+45) (x-40) = 0

⇒x = (-45), 40

But since speed cannot be in negative.

∴ x = 40 km/hr.

Hence, the original speed of the train is 40 km/h.

Answer 2

Let the speed of train be x km/hr

normal speed

distance=360 km

speed = xkm/hr

S= D/T you know

x = 360/time

Time =360/ x

D=360km

S=(x+5)km/hr

T=360/x -1

S=D/T

X=360/(360/x-1)

(x+5) (360/x-1)= 480 .(1)

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