Question

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less for the same journey. Find the speed of train​

Answer 1

Step-by-step explanation:

let speed of train x km/h

according to questions

speed=distance/time for first condition

x=360/time1 then

time1=360/x

then second condition

Time 2=360/x+5

then first value is more

time1-time2=time

360/x-360/x+5=1

then simplification

x2+5x-1800=0 (solve quadratic equation)

x2+45x-40x-1800=0

x (x+45)-40(x+45)=0

(x+45)or (x-40)=0

then value of x =40

speed of 40km/h

Answer 2

Answer:

Let the original speed of the train be x km/h.

Time taken to cover a distance of 360 km =  360/x hours.

New speed of the train = (x+5) km/h.

Time taken to cover a distance of 360 km at new speed = 360/x+5 hours.

Since, the train takes 1 hour less time,

∴ 360/x - 360/ x+5 = 1

⇒360 (x+5-x)/x(x+5) = 1

⇒360 (5) = x² + 5x

⇒1800 = x² + 5x

⇒x² + 5x - 1800 = 0

⇒x² + 45x - 40x - 1800 = 0

⇒x (x+45) - 40( x +45) = 0

⇒(x+45) (x-40) = 0

⇒x = (-45), 40

But since speed cannot be in negative.

∴ x = 40 km/hr.

Hence, the original speed of the train is 40 km/h.

hope it helps u

thanks...