Question

A train travels 360 km at a uniform speed. If the speed had been 5 km/h more, it would
have taken 1 hour less for the same journey. Find the speed of the train.​

Answer 1

Step-by-step explanation:

Let the speed of the train be = x km/hr

Actual time taken by train = Distance / speed

==> (360 / x) hrs.

If the speed would be 5 kmph more,

now, new speed = (x+5) km/hr

Now,

new time taken = (360/x+5) hrs

By the given condition

Original time - new time = 1 hr

(360/x) - (360/x+5) = 1

$\frac{360(x + 5) - 360(x)}{(x)(x + 5)} = 1$

On solving this, we get

360 [(x+5)-(x)] = x² + 5x

360 × 5 = x² + 5x

1800 = x² + 5x

x² + 5x - 1800 = 0

x² + 45x - 40x - 1800 = 0

x(x+45) - 40(x+45) = 0

(x-40) (x+45) = 0

Therefore,

x = 40

OR

x= -45

But speed is never negative

therefore x = 40 km/hr is acceptable

THEREFORE THE SPEED OF THE TRAIN ==>

40 Km / Hr

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Answer 2

Answer:

this is your ans

I hope it helps