A train travels 360 km at a uniform speed . If the speed had been 5km/h more, it would have taken 30 minutes less for the same journey . Find the speed of the train.
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40km/HR is the speed of the train
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let the speed be x km/Hr
speed = distance /time
x = 360/ time
time = 360/x eq1
Now when speed increased by 5km/Hr
speed = (x + 5)km/hr
time would be 1/2 hr less so
time = 360/x - 1/2 = (720 - x) / 2x
speed = distance / time
x + 5 = 360 / ((720 - x) / 2x)
(x + 5)(720-x) /2x = 360
(x + 5)(720-x) = 720x
720x -x^2 + 3600 - 5x = 720
x^2 - 715x - 2880 = 0
Solve above equation u will get the speed .
Thanks
speed = distance /time
x = 360/ time
time = 360/x eq1
Now when speed increased by 5km/Hr
speed = (x + 5)km/hr
time would be 1/2 hr less so
time = 360/x - 1/2 = (720 - x) / 2x
speed = distance / time
x + 5 = 360 / ((720 - x) / 2x)
(x + 5)(720-x) /2x = 360
(x + 5)(720-x) = 720x
720x -x^2 + 3600 - 5x = 720
x^2 - 715x - 2880 = 0
Solve above equation u will get the speed .
Thanks
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