A train travels a distance of 480 km at a uniform speed if the speed had been 8 kilometre per hour less than it would have taken 3 hours more to cover the same distance we need to find the speed of a train
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..............
480Y=480(Y−8)+3Y(Y−8)
Y2−8Y−1280=0
(−40)(Y+32)=0
Y=40,−32
..............
***********Suppose the speed of the train is Y km/h.
It takes 480Y hours to travel
, but if the speed were
8 km/h slower, it would take 480Y−8 hours.
we've got the equation:
480Y−8 = 480Y +3
480Y=480(Y−8)+3Y(Y−8)
Y2−8Y−1280=0
(−40)(Y+32)=0
Y=40,−32
, so the speed
is Y=40 km/h.
so the difference is three hours
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