A train travels a distance of 480 km at a uniform speed if the speed had been 8 km per hour less than it would have taken 3 hours more to cover the same distance find the speed of the train
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Distance travelled by the train = 480 kmLet the speed of the train be x kmph Time taken for the journey = 480/x Given speed is decreased by 8 kmph Hence the new speed of train = (x – 8) kmph Time taken for the journey = 480/(x – 8)  1280 = x2 – 8x x2– 8x – 1280 = 0 On solving we get x = 40Thus the speed of train is 40 kmph
INFAMOUSWIZARD:
i think you can solve the quadratic equation
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Let us consider,
speed of train = x km/h
And
Time taken to travel 480 km = 480 (x) km/h
As per second situation, the speed of train = (x – 8) km/h
As given, the train will take 3 hours more to cover the same distance.
Therefore, time taken to travel 480 km = (480/x) + 3 km/h
As we know,
Speed × Time = Distance
Therefore,
(x – 8)[(480/x) + 3] = 480
⇒ 480 + 3x – (3840/x) – 24 = 480
⇒ 3x – (3840/x) = 24
⇒ 3x^2 – 24x – 3840 = 0
⇒ x^2 – 8x – 1280 = 0
Hence, x^2 – 8x – 1280 = 0 is the required representation of the problem mathematically
Hope it's Helpful.....:)
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