A train travels a distance of 480 km at uniform speed if the speed had been 8 km per hour less than it would have taken 3 hours more to cover the same distance find the usual speed of the train
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here is your answer
let the velocity of train be V
time taken to cover the distance=t
given if velocity (V') isby( V-8) then time taken is( t')=t+3
distance=V×t
d=V×t........1
d=V'×t'. so from two equations
V'×t'=V×t
(V-8)(t+3)=480
by solving equation we get
3V-8t=24
from equation 1
3V-8×(480/V)=24
we get V^2-8V-1280=0
by solving the equation we get
V=40km/hour (roots are 40&-33 but velocity cant be negative so answer is 40)
t=480/40
t=12hours
if V'=32km/hr
t'=480/32
t'=15km/hr
hope the answer is helpful.
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