Question

A train travels at 75 km/h for 0.44
hour, 60 km/h for next 0.33 hours
and then 65 km/h for the next 0.61
hour

what is the average

speed of trip? ​

Answer 1

Given :-

★ A train travels at 75 km/h for 0.44

hour, 60 km/h for next 0.33 hours

and then 65 km/h for the next 0.61

hour.

To Find :-

★ What is the average speed of the train?

Solution :-

At first, we have to find total distance.

We know,

Distance = Speed × Time

Hence,

✰ Distance, D(1) ( When speed 75 km/hr & time 0.44 hrs)

= 75 × 0.44

= 33 km

✰ Distance, D(2) ( When speed 60 km/hr & time 0.33hrs)

= 60 × 0.33

= 19.8 km

✰ Distance, D(3) ( When speed 65 km & time 0.61 hrs)

= 65 × 0.61

= 39.65 km

Therefore,

total distance

= D(1) +D(2) + D(3)

= (33 + 19.8 + 39.65) km

= 92.45 km

Total time

= ( 0.44 +0.33 + 0.61) hrs

= 1.38 hrs

We know,

Average speed = Total distance /Total time

Now, put the given values

Average speed = Total distance /Total time

= 92.45 / 1.38

= 66.993 km/hr

Hence,

Average speed of the train is = 66.993 km/hr

$\bold\blue{@ItzSilentColleen }$

Answer 2

Answer:

Given :-

★ A train travels at 75 km/h for 0.44

hour, 60 km/h for next 0.33 hours

and then 65 km/h for the next 0.61

hour.

To Find :-

★ What is the average speed of the train?

Solution :-

At first, we have to find total distance.

We know,

Distance = Speed × Time

Hence,

✰ Distance, D(1) ( When speed 75 km/hr & time 0.44 hrs)

= 75 × 0.44

= 33 km

✰ Distance, D(2) ( When speed 60 km/hr & time 0.33hrs)

= 60 × 0.33

= 19.8 km

✰ Distance, D(3) ( When speed 65 km & time 0.61 hrs)

= 65 × 0.61

= 39.65 km

Therefore,

total distance

= D(1) +D(2) + D(3)

= (33 + 19.8 + 39.65) km

= 92.45 km

Total time

= ( 0.44 +0.33 + 0.61) hrs

= 1.38 hrs

We know,

Average speed = Total distance /Total time

Now, put the given values

Average speed = Total distance /Total time

= 92.45 / 1.38

= 66.993 km/hr

Hence,

Average speed of the train is = 66.993 km/hr

\bold\blue{@ItzSilentColleen }@ItzSilentColleen