A train travels at a certain
average speed for a distance of 54km and then travels
at an average speed of 6 km/hr more than the first speed. If
it takes 3 hours to complete the total journey, what is its first speed?
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Answer:
hope you get your answer
Step-by-step explanation:
Distance =54km
Let the average speed be x
Distance =63 km
The average speed to cover this distance =x+6
Total time taken =3hr
DS=t
∴54x+63x+6=3
54(x+6)+63xx(x+6)=3
54x+324+63x=3x2+18x
=> 3x2−99x−324=0
=> x2−33x−108=0
(x−36)(x+3)=0
x=36or−3
x=−3 is not admissible
Hence x=36km/hr is the speed
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