a train travels the first 15km at a uniform speed of 30km|h next 10km at a uniform speed of 20km|h and final 75km at a uniform speed of 50km|h . the average speed for the entire journey of the train is
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Given :-
First 15 km at a uniform speed of 30km/h.
Next 75km at at a uniform speed of 50km/h.
Last 10km/h at a uniform speed of 20km/h.
Time 1st = distance /speed = 15/30
Time 2nd = distance /speed = 75/50
Time 3rd = distance /speed = 10/20

Total distance = 15km+75km+10km = 100km

Hence,
Average speed of train is 40km/h
Hope it helps you
Given :-
First 15 km at a uniform speed of 30km/h.
Next 75km at at a uniform speed of 50km/h.
Last 10km/h at a uniform speed of 20km/h.
Time 1st = distance /speed = 15/30
Time 2nd = distance /speed = 75/50
Time 3rd = distance /speed = 10/20
Total distance = 15km+75km+10km = 100km
Hence,
Average speed of train is 40km/h
Hope it helps you
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