A train Travels the first 30 km of 120 km track with a uniform speed of 30 km/h . what should be the speed of the train to cover the remaining distance of the track so that its average speed is 60 km/hr for the entire trip.
Answers
Answered by
1
For this problem, We have to use the average Speed formula.
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As it is given that,
Speed in the first Part of the journey,S(1)
= 30 km/ hr
Speed in the 2nd Part of the journey,S (2)
= ? km/hr
Average Speed(s) = 60km/hr
So by using,
Average speed (s)= [S(1) + S(2)]/2
60 = [30 + S (2)]/2
120 = 30 + S (2)
(S) = 120-30
= 90 km/hr
==================================☆
As it is given that,
Speed in the first Part of the journey,S(1)
= 30 km/ hr
Speed in the 2nd Part of the journey,S (2)
= ? km/hr
Average Speed(s) = 60km/hr
So by using,
Average speed (s)= [S(1) + S(2)]/2
60 = [30 + S (2)]/2
120 = 30 + S (2)
(S) = 120-30
= 90 km/hr
Answered by
0
ANSWER
In the first 30 km speed of the train, v1 = 30 km/h
Speed of the train in the next 90 km, v2 (to be determined)
Average speed = 60 km/h = (v1 + v2)/2
= (30 km/h + v2)/2
→ v2 = 90 km/h
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