A train was moving at the rate of 36km/have. when breaks were applied. it come to rest in a distance of 200 metres . calculate the retardation produced in train.
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ezaz14:
thanks
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hey mate here's your answer
initial velocity=36km/hr ie.10m/s
distance=200m
retardation=???
by formula
s=u^2/2a
200=10^2/2a
2a=100/200
a=0.5/2
a=0.25m/s^2
thus.... retardation produced is 0.25m/s^2 in opposite direction
plzz Mark as brainlist if it helps
initial velocity=36km/hr ie.10m/s
distance=200m
retardation=???
by formula
s=u^2/2a
200=10^2/2a
2a=100/200
a=0.5/2
a=0.25m/s^2
thus.... retardation produced is 0.25m/s^2 in opposite direction
plzz Mark as brainlist if it helps
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