A train weighing 100 metric ton is running on a level track with a uniform speed of 72 km/h .If the frictional resistance amounts to 0.5 kg per metric ton ,find power of the engine.
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Answered by
18
Answer:velocity=72×(1000÷3600)=20m/s
F=0.5×100×9.8
Power=F×v
=0.5×100×9.8×20
=9800W
=9.8 kW
Explanation: Since a=0 as speed is uniform.
Therefore,force of friction=force applied on train.
Answered by
12
Answer:
Mass of the train is,
m = 105 kg
Uniform speed of the train is, u = 72 km/h = 20 m/s
Frictional force per metric ton is = 0.5 × 9.8 N = 4.9 N
Therefore, frictional force on the train = 4.9 × 100 = 490 N
Since, the train has to overcome this frictional force to maintain a constant speed, the power is given by,
Power = (force)(speed) = 490 × 20 = 9800 W
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