Question

a trains initially at rest picks up a velocity of 180 km per hour in 4.5 seconds calculate acceleration and distance covered by the train

Answer 1

We know,
a=(v-u)/t
we have,
u=0
v=180km/h=50m/s.
t=4.5 sec.
So,

a=(50-0)/4.5
a=50/4.5
11.12 m/s (approx)

b.


We know distance (s) = ut+1/2at²

so,

(0*4.5)+1/2*11.12*4.5*4.5
So distance (s) = 1/2*210
s=105

Hope it helps.
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