Question

A transformer has 1000 turns and 240 voltage, 0.2 A in the primary coil. if the current through secondary coil is 0.4 A. Find out the voltage and number of turns in the secondary coil

Answer 1

Explanation:

hope answer is helpful

Answer 2

Answer:

A transformer has 1000 turns and 240 voltage, 0.2 A in the primary coil. if the current through the secondary coil is 0.4 A, the voltage and number of turns in the secondary coil are 120v and 500 respectively

​Explanation:

• In a transformer, there is a primary coil with a number of turns $N_{1}$ voltage, and current through it is $I_{1}$. In the secondary coil, the number of turns is $N_{2}$ voltage is $V_{2}$ and current is $I_{2}$

• The relation connecting these parameters is given by the formula

        $\frac{N_{1} }{N_{2} } =\frac{V_{1} }{V_{2} }=\frac{I_{2} }{I_{1} }$

From the question, we have

current in the primary coil $I_{1} =0.2A$

current in the secondary coil $I_{2} =0.4A$

the voltage in the primary coil is $V_{1} =240v$

the number of turns in the primary coil $N_{1} =1000$

the voltage in the secondary coil $V_{2} =\frac{V_{1} }{I_{2} } I_{1}$

⇒$V_{2} =240*\frac{0.2}{0.4} =120v$

the number of turns in the secondary coil $N_{2} =\frac{V_{2} N_{1} }{V_{1} }$

⇒ $N_{2} =120/240*1000=500$