Question

A transition metal ‘X’ has a configuration [Ar]3d5 in its 3+ oxidaton state.Its atomic number is:

Answer 1

[ Ar]3d^5 let A is the elements

first atomic number of Ar is 18 and add 5 then number of electrons in A+3
oxidation means loss of electrons ,
so, +3 charge means 3 electrons loss by A then it forms A +3

so , actually number of electrons in A = 23 + 3 = 26

we know,
in neutral element number of electrons = number of protons = atomic number
so,
atomic no of A = 26

Answer 2

Answer:

electronic configuration of metal is

1s2, 2s2,2p6, 3s2, 3p6, 3d5

so there are 23 electrons in total

Here oxidation state is valency so metal has valency of 3 that means it has donated its 3 electrons.

no of protons will remain same i.e.,

23+3=26

no of protons is atomic number only.

atomic number of metal is 26