a
Translate the following into logical notation. Let the universe of discourse be the
real numbers.
For any value of x, x is non-negative.
b. For every value of x, there is some value of y such that x.y = 1
There are positive values of x and y such that x.y > 0
d. There is a value of x such that, if y is positive then x + y is negative.
W.
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Answer:
4 + 4 + 6 = is the right answer
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