Question

A transparent ( glass ) sphere has a small , opaque dot at it's center. Does the apparent position of the dot appear to be the same as it's actual position when observed from outside ?


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Answer 1

let refractive index of glass n1 = n

refractive index of air n2 = 1

Then u = - R ( radius of sphere ) ; radius of curvature R = - R

Using n2 / v - n1 / u = ( n2 - n1 ) / R

1 / v - n / ( - R) = (1 - n ) / ( - R ) => 1/v +

n/ R = ( n-1) / R

after solving this equation, we get

image distance v = R

thus we can say that the image distance and object distance are equal and that

the apparent position of dot is the same as its actual position.

it is independent of the refractive index

of the material of the sphere.

I hope it helps you Akka....

naku vaccheysindhi physics sums...

Answer 2

"There will be no change in the position of an opaque dot at the centre of a transparent glass sphere when a person observe it from the outside." All the rays that comes out from an object that kept at the centre of a transparent sphere will be normal to the surface of the sphere."

I hope it helps you mate ✨