Question

A trapezium ABCD,in which AB parallel CD and AD =BC.if angle D=70°,then find the measure of angle C​

Answer 1

hey the answer is ....



in an isosceles trapezium the base angles r equal


so..

angle D = ANGLE C

70 = 70



HOPE IT HELPS UU FRND

Answer 2

Given:

• ABCD is a trapezium
• AB || CD
• ∠D = 70°

To Find:

• The measure of ∠C

Solution:

• First, draw a perpendicular line A from CD to meet CD at M and a perpendicular B on CD to meet N.
• Now consider, ΔADM and ΔBNC,
• ∠AMD = ∠BNC (Both are 90°)
• AM = BN (Distance between the parallel lines)
• AD = BC (Given)
• From the above obtained information we can say that, ΔADM ≅ ΔBNC
• Hence, ∠C = ∠D = 70°

∴ The measure of ∠C = 70°.