if sin x =√5/3 and π/2 <x<π, find the value of sin x/2
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Answer:
cos(x) = -sqrt%281+-+sin%5E2%28x%29%29 = -sqrt%281-%283%2F5%29%29 = -sqrt%281+-+9%2F25%29 = -sqrt%28%2825-9%29%2F25%29 = -sqrt%2816%2F25%29 = -4%2F5%29.
The sign "-" before the square root is because pi/2 < x < pi and cosine is negative in QII.
Now, knowing sin(x) and cos(x), you can easily calculate the remaining functions on your own.
Step-by-step explanation:
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