a trapezium of area 105 cm^2 has parellel sides of length 5 cm and 9 cm.How far apart are the parellel sides
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The area, A, of a trapezium is given by the formula:
A = (h/2)(a + b) where h is the height of the trapezium and a and b are the lengths of the parallel sides.
From the problem statement, we know that A = 105 cm2 and (a + b) = (5 cm + 9 cm) = 14 cm. h is the unknown height we are trying to find. Now plug these values back into the formula for the area of a trapezium:
105 = (h/2)*(14) = h*7
Now you can solve for h.
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area of trapezium = 1/2(sum of parallel side) height
105 = 1/2 (5+9) × h
105 × 2/14=h
15=h
height = 15 cm
faizalgenious:
thank you lot
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