Question

A traveler traveled for 6 hours and covered a distance of 520 km. He traveled the first 260 km by car, and the rest of the way by train. The average speed of the car is twice the average speed of the train. What is the average speed of the train?

Answer 1

We know that,

$\space\space \space \space\space \space \space\space \space \space\space \space \space\space \space \space\space \space \space\space \space \space\space \space \sf \: { \red{Time = \frac{distance}{ Speed}}}$

According to the question,

• Let Speed of Train be X kmph
• Speed of Car= 2X

Given that:

• Distance traveled by Car= 260 km.
• Distance travelled by Train = 260 km
• Total time taken: 6 hours

Equation formed is:

$\sf \: \frac{260}{2x} + \frac{ 260}{x}= 6 \\ \\ \sf \: = 260+520 = 12x \\ \\ \sf \: = 12x = 780 \\ \\ \sf \: x = 65$

Hence,

• x= 65 kmph which is the speed of the train.
• Speed of the csr which is double is 130 kmph.

$\sf{@WildCat7083 }$