Question

A travelling microscope is focussed on to a scratch on the bottom of a beaker. Water of refractive index 4/3 is poured in it. Then the microscope is to be lifted through 2cm focus it again. Find the depth of the water

1) 4cm
2) 8cm
3) 8/7cm
4) 8/3cm​

Answer 1

Answer:

Depth of water in the container is 8 cm

Explanation:

As we know that shift of microscope to focus the bottom of the container is given as

$\frac{\mu_2}{d_i} = \frac{\mu_1}{d_o}$

here we have

$\mu_2 = 1$ due to air

$\mu_1 = \frac{4}{3}$ due to water

now we have

$d_i = \frac{\mu_2}{\mu_1} d_o$

$d_i = \frac{3}{4} d_o$

so we have

$d_o - d_i = 2cm$

$d_o(1 - \frac{3}{4}) = 2 cm$

$d_o = 8 cm$

#Learn

Topic : Refraction of light

https://brainly.in/question/6709448

Answer 2

Answer: 8 cm

Explanation :

d = ď(1 - 1/ų)

2 = ď ( 1 - 1/(4/3))

2 = ď ( 1 - 3/4)

2 = ď ( 1/4)

ď = 4 × 2

ď = 8 cm.

                _ by Shivapotti.

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