A tree 25m high broke at a point 8m above the ground but did not separate. 3
Its top touched the ground. At what distance is the top of the tree from its bottom?
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33 meter............................
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Question -
A tree 25m high broke at a point 8m above the ground but did not separate. Its top touched the ground. At what distance is the top of the tree from its bottom?
Answer -
Note : Refer to the attachment for figure
As per given in the Question ,
We have the following points ,
- Length of tree was 25 m
- If it broke at a point of 8 m then ,
- the length of broken tree would be 17 m ( 25 - 8 = 17 m )
So by applying Pythagoras theorem we will get the length of base ,
(AC)² = (CB)² + (BA)²
(17)² = 8² + (BA)²
289 = 64 + (BA)²
289 - 64 = (BA)²
225 = (BA)²
BA =
BA = 15 m
Hence , the distance from the top of the tree from its bottom is 15 m
What is Pythagoras theorem ?
The Pythagoras theorem states that the square of Hypotenuse of a triangle will be equal to the sum of square of bothe the other sides .
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