Question

a tree break due to a storm and the broken bends so that top of the tree touches the ground making an angle of 30 with it The height of the unbroken part of tree is 4m. The original height of tree was​​

Answer 1

Answer:

8m

Step-by-step explanation:

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Answer 2

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Let AC be the broken part of the tree .

$\therefore$ Total height of the tree $= AB + AC$

In right triangle $ABC$

$cos30° = \frac {BC}{AC}$

$\implies \frac{\sqrt{3}}{2} = \frac {8}{AC}$

$\implies AC = \frac {16}{\sqrt{3}}$

Also , $tan30° = \frac{AB}{BC}$

$\implies \frac{1}{\sqrt{3}} = \frac{AB}{8}$

$\implies AB = \frac{8}{\sqrt{3}}$

Therefore , the total height of the tree

$= AB + AC = \frac{8}{\sqrt{3}} + \frac{16}{\sqrt{3}} = \frac {24}{\sqrt{3}} m$