Question

A tree broke from a point but did not separate. If the point from where it broke is 7 m above the ground and its top touches the ground at a distance of 24 m from its foot , find out the total height of the tree before it broke .
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Answer 1

Step-by-step explanation:

Thus the total height of tree is AB + BC = 7+25 =32m

Answer 2

GIVEN :-

• A tree broke from a point but did not separate. If the point from where it broke is 7 m above the ground and its top touches the ground at a distance of 24 m from its foot.

TO FIND :-

• Height of the tree before it broke.

SOLUTION :-

(Kindly refer the attachment.)

• Firstly , we will make a rough diagram according to the given situation. Let AB be the total height of the tree. Let O be the point from where , the tree broke. A'O=OA as it's the same part broken down.

Now , ∆OBA' is right angled at O.

So, By Pythagoras theorem,

A'O² = A'B² + BO²

We have ,

• A'B =24m
• BO = 7m

Putting values,

→ A'O² = 24² + 7²

→ A'O² = 576 + 49

→ A'O² = 625

→ A'O = √625

→ A'O = 25m

We know , A'O = OA = 25m.

Height of tree = OA + OB

Height of tree = 25m + 7m

Height of tree = 32m

Hence , height of tree before it broke was 32m.