Question

A tree broke from a point but did not separate its top touch the ground at a distance of 24 m from its base is a point where it broke is at the height of 7 m from the ground what is the total height of a tree??​

Answer 1

Answer:

As the distance of tip is 24 m from the base of the tree and it broke at a height of 7 m.

AB = 7 m

AC = 24 m

In triangle ABC, Applying Pythagoras theorem

Total height of tree = AB+BC=7+25=32 m

Answer 2

★ Answer ★

• Total height of tree = 25+ 7 = 32 m .

★ Given :-

• The tree top touched the ground at a distance of 24 m from its base. If the point where it broke is at the height of 7 m from the $ground$.

★ Have to find :-

• What is the total height of the tree?

★ Solution :-

Now , In ∆ ABC

Simply applying the Pythagoras Theorem :-

↠ ( Hypotense ) ² = (Perpendicular) ² + ( Base) ²

↠( Hypoteneous² ) = ( 24² ) + ( 7² )

↠ ( Hypoteneous² ) = 576 + 49

↠ ( Hypoteneous² ) = 625

↠ Hypoteneous = √625

↠ Hypoteneous = 25

Now the part which touched the ground where it broke is at the height of 7 m from the ground will also be added to the total height of the tree.

The total height of tree

= 25+ 7

= 32 m