A tree broken at a point but not separated. its top touches the ground at a distance of 50√2 cm from the ground base. find the hight of rest part of tree. if broken part of tree is of 100 cm.
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The height of rest part of tree is :
A tree broken at a point but not separated. its top touches the ground at a distance of 50√2 cm from the ground base. If broken part of tree is of 100 cm.
1. Let the triangle formed be ∆PQR
2. We have given that, PQ = 100 cm, QR = 50√2 cm
3. We have to find length of side PR
4 Now, applying Pythagoras theorem on ∆PQR
PQ^2 = PR^2 + QR^2
PR^2 = PQ^2 - QR^2
= (100)^2 - (50√2)^2
= 10000 - 5000
= 5000
PR = √5000
= 50√2 cm
5 Hence, the height of rest part of tree is 50√2 cm
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