A tree falls. Its height is 5cm and its top touches the ground. 12cm. Find the actual height?
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Let A’CB represents the tree before it broken at the point C and let the top A’ touches the ground at A after it broke. Then ΔABCΔABC is a right angled triangle, right angled at B.
AB = 12 m and BC = 5 m
Using Pythagoras theorem, In ΔABCΔABC
(AC)²=(AB)²+(BC)²
(AC)²=(12)²+(5)²
(AC)²=144+25
(AC)²=169
⇒⇒ AC = 13 m
Hence, the total height of the tree = AC + CB = 13 + 5 = 18 m.
AB = 12 m and BC = 5 m
Using Pythagoras theorem, In ΔABCΔABC
(AC)²=(AB)²+(BC)²
(AC)²=(12)²+(5)²
(AC)²=144+25
(AC)²=169
⇒⇒ AC = 13 m
Hence, the total height of the tree = AC + CB = 13 + 5 = 18 m.
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