A tree is broken a height of 4m from the ground. Its top touches the ground at a distance of 3m from the base of the tree. Find the original height of the tree.
Answers
Answered by
0
Answer:
18 m
Step-by-step explanation:
Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.
AB=12m and BC=5m
Using Pythagoras theorem, In ΔABC
(AC)
2
+(AB)
2
+(BC)
2
⇒(AC)
2
=(12)
2
+(5)
2
⇒(AC)
2
=144+25
⇒(AC)
2
=169
⇒AC=13m
Hence, the total height of the tree=AC+CB=13+5=18m.
Answered by
0
Answer:
5m
Step-by-step explanation:
the broken is turned to a right angle triangle where
the height is 4m
the base is 3m
and we have to find the perpendicular
by adding the square of 3 and 4 and then under root the sum.
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