A tree is broken at a height of 15 cm from the ground and its top touches the ground at the distance of 20 cm from the base of the tree is the original height of the tree is 20 x k and find k
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Question:
A tree is broken at a height of 15 cm from the ground and its top touches the ground at the distance of 20 cm from the base of the tree is the original height of the tree is 20 x k and find k
Solution:
Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke.
Then, Triangle ABC Is a right angled triangle, at B.
=> AB = 20 cm & BC = 15 cm
Using Pythagoras theoram,
In triangle ABC,
=> (AC)^2 = (AB)^2 + (BC)^2
=> (AC)^2 = (20)^2 + (15)^2
=> (AC)^2 = 400 + 225
=> (AC)^2 = 625
=> AC = Under Square Root (625)
=> AC = 25
Therefore, the total height of the tree(A'B) is:
=> A'C + CB
=> 25 + 15
=> 40 cm
Hence, The Value of K is 2.
Hope It Helps!
Question:
A tree is broken at a height of 15 cm from the ground and its top touches the ground at the distance of 20 cm from the base of the tree is the original height of the tree is 20 x k and find k
Solution:
Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke.
Then, Triangle ABC Is a right angled triangle, at B.
=> AB = 20 cm & BC = 15 cm
Using Pythagoras theoram,
In triangle ABC,
=> (AC)^2 = (AB)^2 + (BC)^2
=> (AC)^2 = (20)^2 + (15)^2
=> (AC)^2 = 400 + 225
=> (AC)^2 = 625
=> AC = Under Square Root (625)
=> AC = 25
Therefore, the total height of the tree(A'B) is:
=> A'C + CB
=> 25 + 15
=> 40 cm
Hence, The Value of K is 2.
Hope It Helps!
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