Question

A tree is broken at a height of 3 m from the ground and its top touches the ground
at a distance of 4 m from the base of the tree. Find the original height of the tree​

Answer 1

Answer:

√hypotenuse = √base+√perpendicular

x square=4 square + 3 square

=16+9

x square =25

x =√25

x=5m

original height of tree=3m+5m

=8m answer

Answer 2

Given:-

• A tree is broken at a height of 3 m from the ground and its top touches the ground at a distance of 4 m from the base of the tree.

To find:-

• Original height of tree.

Solution:-

Diagram is in attachment

Let tree broken at a height be AB.

And the distance between the top of tree and base of tree be BC.

Length of broken tree be AC.

We know that,

If one side of right angle triangle is not given then, We use Pythagoras theorem that is,

◆ (Hypotenuse)² = (Base)² + (Perpendicular)²

So,

Perpendicular = AB = 3m

Base = BC = 4m

Hypotenuse = AC = ?

Put value of Base and Perpendicular in formula,

➝ (AC)² = (AB)² + (BC)²

➝ (AC)² = (3)² + (4)²

➝ (AC)² = 9 + 16

➝ (AC)² = 25

➝ AC = √25

➝ AC = 5 cm

Length of broken tree is 5 cm.

Original height of tree = Length of broken tree + Height of tree from where tree broken.

Height of tree from where tree broken is 3 m

So,

➝ 5 + 3 m

➝ 8 m

Therefore,

Original height of tree is 8 m.