A tree is broken at a height of 3m from the ground and its top touches the ground at a distance of 4 metre from the base of the tree find the original height of the tree
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Answer:
we can take this in the form of a triangle with
base AB = 4m
height of tree left standing BC = 3m
height of broken tree = AC
applying Pythagoras theorem,
(AC)∧2 = (AB)∧2 + (BC)∧2
(AC)∧2 = 4∧2 + 3∧2 = 16 + 9
AC = √25
AC = 5m
height of tree that is broken = 5m
height of tree left standing = 3m
so total height = 5 + 3 = 8m
original height of tree = 8m
hope this helps.
Answered by
2
Answer:
thankyou for your answer
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