Question

A tree is broken at a height of 4m from the ground. Its top touches the ground at

a distance of 3m from the base of the tree. Find the original height of the tree.​

Answer 1

Answer:

Thus, the original height of the tree = AB+BC+CA=3m+4m+5m=12m

Step-by-step explanation:

take the sides of the triangle to be ABC in ABC.

Let be AB x.

(Pythagoras theorem applied )

AB² =BC²+ CA²

AB²=(3m)²+(4m)²

AB²=9²+16²

AB²=25²

AB²=√25

AB=5m