A tree is broken at a height of 4m from the ground. Its top touches the ground at
a distance of 3m from the base of the tree. Find the original height of the tree.
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Answer:
Thus, the original height of the tree = AB+BC+CA=3m+4m+5m=12m
Step-by-step explanation:
take the sides of the triangle to be ABC in ABC.
Let be AB x.
(Pythagoras theorem applied )
AB² =BC²+ CA²
AB²=(3m)²+(4m)²
AB²=9²+16²
AB²=25²
AB²=√25
AB=5m
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