A tree is broken at a height of 5 m from the ground and its top touches the ground at a distance of 12 m from the base of the tree. Find the original height of the tree.
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Let A'CB be the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, at B. Hence, the total height of the tree(A'B) = A'C + CB = 13 + 5 = 18 m.
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18 m
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