Question

A tree is broken at a height of 5cm from the ground and it's top touches the ground at a distance of 12m from the base of the tree. find the original height of the tree. ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Let A’CB be the tree before it broken at the point C and let the top A touch the ground at A after it broke. Then ΔABC is a right angled triangle, at B.

AB = 12 m

BC = 5 m

Using Pythagoras theorem,

In ΔABC

$(AC)²=(AB)²+(BC)²$

$(AC)²=(12)²+(5)²$

$(AC)²=144+25$

$(AC)²=169$

$AC = \sqrt{169}$

AC= 13 m

Hence, the total height of the tree(A’B) = A’C + CB = 13 + 5 = 18 m.