Question

A tree is broken at a height of 7 metres from the ground and its top touches the ground at a distance of 15 metres from the base of the tree find the original height of the tree

Answer 1

Answer:

is the final answer of this question

Answer 2

Answer:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)2 +(AB) 2 +(BC) 2

⇒(AC) 2 =(12) 2 +(5) 2

⇒(AC) 2 =144+25

⇒(AC) 2 =169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.