Question

A tree is broken at a height of 7m from the ground and its top touches the
ground at a distance of 15m from the base of the tree. Find the original height
of the tree.

Help Me​

Answer 1

Answer: 18m

Step-by-step explanation:

Let A'CB represents the tree before it broken at the point C and let the top A' touches the ground at A after it broke. Then ΔABC is a right angled triangle, right angled at B.

AB=12m and BC=5m

Using Pythagoras theorem, In ΔABC

(AC)  

2

+(AB)  

2

+(BC)  

2

 

⇒(AC)  

2

=(12)  

2

+(5)  

2

 

⇒(AC)  

2

=144+25

⇒(AC)  

2

=169

⇒AC=13m

Hence, the total height of the tree=AC+CB=13+5=18m.