Question

A tree is broken at a height of 9m from the ground and its top touches the ground at a distance of 12m from the base of the tree. Find the original height of the tree. Find the original height of the tree

Answer 1

Let the height of the tree be (h+9)m

In right triangle:-

9^2+12^2=h^2

81+144=h^2

Root225=h

h=15m

hence height of the tree=h+9

=15+9

=24m

Hope it helped❤

Answer 2

Given:

Height of the tree from ground= 9m

Distance of the top of the tree from its base= 12m

To find:

The original height of the tree

Solution:

We can find the solution by following the given process-

From the information given, we know that a triangle has been formed.

The part of the tree still standing is the height, the ground is the base and the fallen part is the hypotenuse.

So, we will find the length of the fallen part of the tree by using the Pythagoras Theorem.

$Height {}^{2} + base {}^{2} = hypotenuse {}^{2}$

Putting the values,

$9 {}^{2} + 12 {}^{2} = hypotenuse {}^{2}$

$81+144= hypotenuse {}^{2}$

$\sqrt{225} = hypotenuse$

Hypotenuse= 15m

The original height of the tree= length of part still standing+ length of the fallen part

= 9+15

=24m

Therefore, the original height of the tree is 24m.