Question

A tree is broken by wind its top touches the ground and a point 10 m from the foot of tree makes an angle of 45 degree length of tree in metres find

Answer 1

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Answer 2

let BC be the distance frm the foot of the tree where the top touches

let AC be broken part

Let AB be still tree part

AB/BC=tan 45

AB/BC =1

AB=BC

SO, AB = 10 M

AB/AC=sin 45

10/AC=1/√2

AC=10√2m

height of the tree = AB+AC

= 10+10√2

=10(1+√2)m

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