A tree is broken over by the wind forms a right angled triangle with the ground if the broken part markes an angle of 60^ with the ground and the top of the tree is how 20m from its base , how tall was the tree ?
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Let △ABC be a right angled triangle where ∠B=90 and ∠C=60
Let x be the length of remaining part of the tree and y be the length of part of tree which is broken.
We know that tanθ=Adjacent side/Opposite side
=BC/AB
half answer is in the photo
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