A tree which was 25m high broke at a point in a storm but did not separate . Its top touched the ground at a distance of 12m from its base. Find the height of the point from the ground at which the tree broke
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the arrangement by which the tree broken forms a right angled triangle whose base is of 12m and height is 25m
height of the tree = 25m
it base = 12m
height of the point from the ground at which tree broke is the hypotenuse of the right angled triangle
using Pythagoras theorem
hypotenuse²= height ²+base ²
hypotenuse² = (25)²+(12)²
hypotenuse² = 625+144 => 769
hypotenuse = √769 = 27.73
hope this helps
height of the tree = 25m
it base = 12m
height of the point from the ground at which tree broke is the hypotenuse of the right angled triangle
using Pythagoras theorem
hypotenuse²= height ²+base ²
hypotenuse² = (25)²+(12)²
hypotenuse² = 625+144 => 769
hypotenuse = √769 = 27.73
hope this helps
Answered by
10
see here tree is straight and so it make 90° with earth
and after Strom it broke and it make triangle so it triangle would be
right angle triangle
suppose
if AB is hight of tree and AM is hight from ground to that point
were tree broken
and AM = X ( suppose)
were it's top touched the ground it distance is AD = 12m
and AB = AM + MB
25 = x + MB
MB = 25-x
here MB is hight of hypotenuse
so apply pythagoras theorem
MB² = AM² + AD²
(25-x)² = x² + (12)²
625 - 50x + x² = x² + 144
50x = 481
x = 481/ 50
and after Strom it broke and it make triangle so it triangle would be
right angle triangle
suppose
if AB is hight of tree and AM is hight from ground to that point
were tree broken
and AM = X ( suppose)
were it's top touched the ground it distance is AD = 12m
and AB = AM + MB
25 = x + MB
MB = 25-x
here MB is hight of hypotenuse
so apply pythagoras theorem
MB² = AM² + AD²
(25-x)² = x² + (12)²
625 - 50x + x² = x² + 144
50x = 481
x = 481/ 50
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