A triangle ABC where AB =½BC and the angle A=90⁰ then find angle C
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Step-by-step explanation:
AB=AC [Given ]
∠A=90
o
∴ ∠C=∠B [ Angles opposite to equal sides are equal ] ---- ( 1 )
In △ABC,
∠A+∠B+∠C=180
o
[ Angles sum property of triangles ]
⇒ 90
o
+∠B+∠C=180
o
⇒ 90
o
+∠B+∠B=180
o
[ From ( 1 ) ]
⇒ 2∠B=90
o
⇒ ∠B=45
o
∴ ∠B=∠C=45
o
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