Question

A triangle and a parallelogram are constructed on the same base such that their areas are equal. If the altitude of the
parallelogram is 150m, find the altitude of the triangle.
is 50cm. Find its area if altitudes of triangle?​

Answer 1

Answer:

Answer

Let the triangle and parallelogram have common base b,

let the Altitude of triangle is h

1

and of parallelogram is h

2

(which is equal to 150m), then

Area of triangle =

2

1

×b×h

1

Area of rectangle =b×h

2

As per question

2

1

×b×h

1

=b×h

2

⇒

2

1

×b×h

1

=b×150×h

1

=150×2=300m

Answer 2

Step-by-step explanation:

Answer:

Let the triangle and parallelogram have common base b,

let the Altitude of triangle is h

1

and of parallelogram is h 2

(which is equal to 150m), then

Area of triangle = 21 ×b×h 1

Area of rectangle =b×h 2

As per question

2

1

×b×h

1

=b×h

2

⇒

2

1

×b×h

1

=b×150×h

1

=150×2=300m