a triangle and a parallelogram are on the same base and between the same parallels.if altitude of triangle is 4 cm and it 's area is 8cm^2 ,find the length of base of parallelogram.
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altitude=4cm
area of triangle = 8cm sq. ( i.e 1/2 ar of ||gm)
2*8= 4*b ( 2*ar of triangle = ar of ||gm or base* height)
16=4h
h=16/4
h=4cm
Verify
if a triangle and a parallelogram are on the same base and between the same parallels, area of triangle= 1/2 area of ||gm.
therefore,
8=1/2*4*4
8=16/2
8=8
therefore, base of the parallelogram is 4 cm. pls mark as 5 stars if this helped! I spent lot of time solving this 4 u.
area of triangle = 8cm sq. ( i.e 1/2 ar of ||gm)
2*8= 4*b ( 2*ar of triangle = ar of ||gm or base* height)
16=4h
h=16/4
h=4cm
Verify
if a triangle and a parallelogram are on the same base and between the same parallels, area of triangle= 1/2 area of ||gm.
therefore,
8=1/2*4*4
8=16/2
8=8
therefore, base of the parallelogram is 4 cm. pls mark as 5 stars if this helped! I spent lot of time solving this 4 u.
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